-4.9x^2+25x=0

Solution for -4.9x^2+25x=0 equation:

-4.9x^2+25x=0

a = -4.9; b = 25; c = 0;
Δ = b2-4ac
Δ = 252-4·(-4.9)·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-25}{2*-4.9}=\frac{-50}{-9.8}
=5+1/9.8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+25}{2*-4.9}=\frac{0}{-9.8}
=0
$